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Posted By Derek Williams Could anyone explain the difference between static weight and dynamic weight for me please.
Derek.
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Posted By Ron Hunter Step gently onto the weighing scales at your local branch of Boots = Static Weight. Jump on them = Dynamic Weight.
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Posted By William Would it be incorrect to suggest that the weight at which a stone is when on the ground is its static weight and the weight or force which it is after it falls 100 metres and then strikes something (maybe the scales!!!) would be the dynamic weight?
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Posted By Ali After studying Physics and applied Maths at a level I still don't understand your terminology. "Weight" is the force of gravity exerted on a load = mg (Newtons) where g=9.81 m/s/s. Apart from slight variations in g over the earth's surface, the weight should remain constant. However, the force exerted by the load can vary with its momentum and angle of travel. Maybe you can be a little bit more specific ? Ali
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Posted By Alan Hoskins There is general confusion regarding weight, which is the term employed to describe a mass influenced by a specific amount of gravity.
As Ali says, this is generally considered to be a factor of 9.81m/s/s on Earth.
Ignoring that terminology then, 'Dynamic' suggests movement, so I would suggest that static weight would apply to, say, a hammer resting on a workbench, whereas dynamic weight would apply to a hammer striking a nail.
More or less what others have said...
Alan
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Posted By Glen Coe The previous analogy's are pretty good.
The one I use for offshore is when a crane picks up a 10 te container its static weight is 10 te.
If it were to pick up the same container from a supply boat in a moderate sea swell it would be a snatch load and that is typically times 2.4 (this was averaged on the data from the recording safe load indicator lifts)ie 24te would be shown as a spike momentarily on the safe load indicator and yes you would see the crane boom bounce a bit.
Hope that helps, but as stated before it is all about inertia and speed.
Cheers GC
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Posted By Kieran J Duignan Derek
I wonder to what extent you are confusing 'static' and 'dynamic' posture, with what you call 'static' and 'dynamic' weight?
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Posted By Adrian Watson What is being confused is static and dynamic loading.
Regards Adrian
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Posted By Adrian Watson What is being confused is static and dynamic loading.
The load is mass x work.
Regards Adrian
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Posted By Derek Williams Hi All,
Many thanks for your input, you have all confirmed what I thought would be the solution, that is something placed gently or something dropped with force.
Regards,
Derek.
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Posted By Steven John Bateson Some basics: mass is the amount of matter in a body and always remains constant. Weight is a Force i.e. mass x acceleration. A body in motion has momentum i.e. mass x velocity. Thus, a body moving with constant velocity has momentum but does not exhert any force. However, when that body is brought to a stop (deceleration i.e. negative acceleration) it will exhert a force i.e. swing a hammer and it has momentum but it doesn't exhert a force until it hits the nail and gets decelerated to a stop. The earth's gravits causes a body to accelerate towards it at 9.81 m per s squared but the earths surface (via the scales) stop us moving. Thus, we exhert a force on the scales that we call weight
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Posted By Robert K Lewis I think it is easier to think of weight in motion (WIM) rather than considering dynamic weight. Using algorithms one can evaluate the weight of an unstable object standing on the load plate, eg an animal, or an object moving across the load plate at a constant speed eg a wagon. Yes if the object is capable of standing still on the load plate one can then gain a static weight.
Do not confuse this with a force exerted when a load hits the load plate which is proportional to mass x velocity. This is not a dynamic weight.
Bob
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Posted By Alan Hoskins That's told us all then Bob... we should not try to work out (guess) the answer obviously. For anyone interested, there's a paper on dynamic weighing of trucks at http://stc.utk.edu/htm/pdf%20files/handi.pdfAlso used in mail sorting apparently. Heavy... Alan
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Posted By Robert K Lewis Its good for sweets as well:-)
Bob
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Posted By Richie Derek,
The only time I have ever come across 'static & dynamic' is in the realm of manual handling. This may be related to your question, given these terms are often used in explaining muscle use when carrying a load.
Static and dynamic pertain to the way in which a muscle (or group of muscles) are used, i.e stooping causing a static overload of the back muscles for instance, causing back pain. Dynamic muscle use tends not to cause such problems, as the muscles are not over stressed.
As an aside, climbers have the term 'pumped' meaning the static over use of a muscle group.
I know, a SortofMaybeKinda type of answer, but I thought you might benefit.
Richie
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Posted By Steven John Bateson Static and dynamic loads often get confused in association with crane lifting plans. The calculations are produced as if the loading was static, when a more accurate analysis would treat it as dynamic because the load is, in fact, in motion. The difference is insignificant in most cases because site controls require the crane to move slowly. Unfortunately sometimes lifting operations may become 'rushed' to the point where too much momentum is built up then decelerated too rapidly. At this point the difference between the approximate calculation (based on statics) and the reality may become sufficiently great to tip the crane over i.e. the crane is moving too fast, the operator hits the brakes for some reason, the load carries on moving and begins to decelerate in the horizontal plane whilst accelerating in the vertical plane (because it's held at a fixed radius by the lifting cable)and generates forces in accordence with Newton's 2nd law of motion
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Posted By Martin Griffith i have a check weigher in work that measures a load at a constant speed. The load is carried on a belt across a distance of half a metre. During that time the load i am measuring is known as a dynamic weight (i.e. the loads is weighed whilst in motion). If the load is simply set on the belt whilst it is not turning the measurement is known as static. On this subject can anybody tell me if the load should be the same weight if it is weighed statically or dynamically? I am having problems calibrating the machine.
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Posted By Tabs Martin wrote: "On this subject can anybody tell me if the load should be the same weight if it is weighed statically or dynamically? "
That depends entirely on the algorithms used by the machine.
It is possible to take the information produced as the item passes over the platform and calculate the mass, and therefore the static weight (mass x force) or therefore (mass x 9.81 m/s/s).
I would suggest though that the normal use of the term "dynamic weight" is not appropriate for the situation you describe.
I would use the fish analogy ...
A 3lb carp dead on the scales will 'weigh' 3 lbs.
A 3lb carp wriggling like heck on a line will 'weigh' considerably more - and I would use a 10lb breaking strain line.
A dynamic load exerts considerably more force than a static load.
Your scales should be able to tell you when a 3lb carp passes over. Your calibration problems might be down to what else is passing over them at the same time (i.e. the belt) - it might not have a consistent thickness ...
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Posted By Mitch Forget load, mass & weight and check your dictionaries for the correct meaning of static and dynamic. If you want to involve "scenarios" in the discussion also consider inertia and momentum.
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Posted By Martin Griffith Mitch sorry, i am aware of the meanings of static and dynamic. The words are used to describe a movement or situation in relation to a specific issue. If my case is moving over a weigher is considered to be dynamic. If the case however is stationary on the weigher it is considered static.
Going back to TABS fish analogy, surely the fish moving will exert a different force every time it moves therefore cannot be a constant force. In my situation the case will have a constant momentum and weight. The belt is of uniform thickness.
My question still remains. If all forces are equal apart from the case moving over the weigher or being static on the weigher, should the resulting weight be the same for both situations?
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Posted By Mitch Martin,
Once you have overcome the inertia, acceleration has ceased and the momentum stabilised the weight/mass, whatever you prefer, will be the same as a static load, the force required to stop the momentum will need to be greater than this due to the kinetic energy hence the formulae quoting gravity at 9.81m/s.
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Posted By Martin Griffith Thanks Mitch.
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Posted By Mitch Martin, should have added, try this experiment. weigh an object as normal on the travelling belt. Then, using the same object, stop the belt with the object over the scales and observe the reading then start the belt and again observe the reading, these should be higher than the original measurement. Regards Mitch
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