Rank: New forum user 
|
I'm looking for some help in figuring out the proper formula for benzene exposures over a 10 hour work day with 2 hours of break time. Max concentration without a respirator.
E=(cxt)/10 C= Ex10/T E is O.5PPM, T is 8 hours C = 0.5 x 10/8 =5/8 = .625
Can anyone tell me if the math is correct?
Thank you
|
|
|
|
|
|
Rank: Forum user
|
Benzene in EH40 is classified as a Carcinogen. If you read Para 7 of EH40, the standard to be achieved is now "as low as resonably practical" - ALARP - because of its carcinogicity, also reiterated within CoSHH. The WEL in effect becomes redundant. It is not a target to comply or reach or achieve. You must in effect do whatver is reasonable to reduce the level to as low as you possibly can, not just below the WEL.
So forget the formula. Do all that you can to lower the exposures.
|
 1 user thanked James Robinson for this useful post.
|
|
|
|
Rank: Super forum user 
|
James is correct and about Benzene being a Carcinogen, so you need to go "ALARP". As regards the calc it is a time weighted average. If, as you say on a ten hour shift there is a 2 hour break (I assume no exposure for this?) the calc would be 0.5 * 8 divided by 8 so you would have the answer as 0.5 ppm. If they still had exposure on break your calc would be correct. If you cannot get "ALARP" I would rigorously review and document your controls, and your logic for this.
|
1 user thanked PIKEMAN for this useful post.
|
|
|
|
You cannot post new topics in this forum.
You cannot reply to topics in this forum.
You cannot delete your posts in this forum.
You cannot edit your posts in this forum.
You cannot create polls in this forum.
You cannot vote in polls in this forum.