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JasonMcQueen  
#1 Posted : 26 July 2010 15:27:19(UTC)
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JasonMcQueen

Im preparing to do a DSEAR assessment at one of our sites and was wondering if anyone could help me out? I've read the Regs, ACoP and BS and have no problem determining the zoning etc, what I do have a problem with is calculating the extent of the zones (vertical and horizontal) from the source. Can anyone provide any clarity on how to do this, and is it actually necessary to do so to complete a suitable assessment? One source I spoke to said that provided I justify the decision on what zoning to assign to the souce, the actual extent isnt necessary. Thanks in advance.
bleve  
#2 Posted : 26 July 2010 15:46:35(UTC)
Rank: Super forum user
bleve

Jason, If you are asking this question, are you sure you are in a position to carry out this assessment? The determination of the extent of a hazardous area depends on a number of factors. i.e. pipeline with flange containing a flammable liquid, the flange will be a secondary source of release and zone 2 will exist. The extent of the zone depends on: the area of the hole or gap at the flange, the pressure and properties of the liquid. In other words a hole or gap at the flange will result in a jet of liquid, the trajectory of the jet can ocurr at any point around the flange (360 degrees) the jet will travel a distance of (X) depending on the pressure within the pipe. The jet will at distance (x) reach an obstruction or the ground, this will form a pool. Depending on temperature,ventilation and physical properties the pool will evaporate at a certain rate. The distance above and beyond the pool will be the extent of the zone. Similar considerations will be necessary for gases (gas density) and dusts (settling velocity) etc
JasonMcQueen  
#3 Posted : 26 July 2010 15:56:54(UTC)
Rank: Forum user
JasonMcQueen

Bleve, I hear you and Im still open to the possibility of handing this out to a third party. As I say, I have no problem determining everything else required such as the chemical properties, LEL/UEL etc, degree of ventilation, grading of release etc etc. Its just solely the issue of calculating the extent of the zones which is an issue. There just seems to be so many variables to make it a straight forward (or reasonably straight forward) calculation.
bleve  
#4 Posted : 26 July 2010 16:01:09(UTC)
Rank: Super forum user
bleve

The extent can be straight forward for a number of scenarios (vents, pumps, bunds, head space etc). However, there will be a number of cases (flange type releases, Powder handling operations) where some thought and calculations are necessary.
JasonMcQueen  
#5 Posted : 26 July 2010 16:26:01(UTC)
Rank: Forum user
JasonMcQueen

I think thats what Im struggling with. Looking at the formulas in BS EN 60079-10 it looks relatively straight forward (assuming all the information necessary is available) but when it comes to estimating the release rate, how do you know the cross section size of, for example a failure in a flange? Surely it would depend on the extent of the failure (i.e. small to total failure)?
ITER  
#6 Posted : 26 July 2010 17:56:31(UTC)
Rank: Forum user
ITER

As well as BS60079-10 you can also use the Institute of Petroleum Guide Pt 15 for calculating hazardous zones. The formula in 60079-10 require you to know the molecular weight(s) of the substances. IP 15, uses a variety of 'standard' leak sizes (holes) - 0.5mm, 1mm, 6mm if my memory serves me right. There is a get out clause in the front of 60079-10 - if the leak is large/gross failure of a pipe then hazardous zoning, as such, is no longer valid. You can then use PHAST software to help determine the extent and consequences of major leaks - extent of flammable zones, direction of drift and concentration of gas/vapour clouds at certain distances. This software also takes into account the weather conditions using the Pascal Stability index system.
antbruce001  
#7 Posted : 26 July 2010 19:21:50(UTC)
Rank: Forum user
antbruce001

All the above is correct. However, provided you are not undertaking anything unusaul you can work within the 'standard' diagrams within the BS and HSE guidance. However, you must justify that it is appropriate to do this. E.g. if you have a flammable gas at low pressure in a pipeline a 1m radius around the flange will be accepted by the HSE (as per the BS for LPG in a pipeline). Don't forget combustable mists. If you have pressurised combustable materials these can give rise to zoned areas (e.g. diesel). Also, note that the 2009 BS standard has a new section on mists that should be referred to. Hope it helps Tony.
bleve  
#8 Posted : 26 July 2010 19:37:36(UTC)
Rank: Super forum user
bleve

As stated there will be a number of cases where exemplars are fit for purpose but again as stated there will be cases where they are not. IP 15 is intended to be applied to petroleum operations the clue is in Instituteof petroleum IP 15. IP 15 is based on engineering judgment only. The use of DNV Phast is fine provided you areable to use the software, have a grasp of first principles i.e rubbish in = rubbish out. Cost of Phast, license & training would buy the services of a professional many times over. Ultimately, these things should be left to a pro but I am sure as in the case of FRA many will take their chances. I do not buy into and never will the one consultant fits all philosophy. FRA and DSEAR are a skill, it is not something you can do overnight and yes I know many will disagree and no I am not particularly interested in debating it. Those that can (good on you) those that think they can (spin the wheel, take your chance & one day see you in court).
bleve  
#9 Posted : 26 July 2010 19:43:34(UTC)
Rank: Super forum user
bleve

You could even have the bonus that not only does the pro know what he/she knows what they are doing but also has Phast and knows how to use it and save even more money. Imagine that. ;)
bleve  
#10 Posted : 26 July 2010 19:45:27(UTC)
Rank: Super forum user
bleve

Remember a cheap risk assessment of any kind can prove to be very expensive.............
JasonMcQueen  
#11 Posted : 26 July 2010 23:07:13(UTC)
Rank: Forum user
JasonMcQueen

I agree but finding a decent consultant isnt that easy. The cost of Phast means that this isnt an option given that the use I'd have is limited to the immediate operations.
ITER  
#12 Posted : 27 July 2010 08:51:46(UTC)
Rank: Forum user
ITER

Jason if you can give a better description of the [plant/process that is subject of your DSEAR assessment, I might be able to give some indications from the relevant hazardous areas etc Substance/gas, pressure, pipe size, tank size, location, ventilation conditions etc etc as relevant. I have Excel spreadsheets already set up with the various BS60079-10 formula etc - just need to plug the numbers in etc. Also have a copy of IP 15. IP 15 has a a series of standard examples e.g. vehicle refuelling hazardous areas etc. I am very familiar with using PHAST software - but no longer use it in my present job, so can't help there
JasonMcQueen  
#13 Posted : 27 July 2010 09:27:27(UTC)
Rank: Forum user
JasonMcQueen

Thanks Iter, The first one is relatively straightforward. We're planning on installing 2 x 12,000L external vertical storage tanks (integrally bunded) which will contain solvent (LEL 3.3%, UEL 19%, Flashpoint 13oC, Density 0.791, Gas relative density 0.791, Ignition Temp 365oC, Group&Temp 2A T2) with natural ventilation. The others are little more difficult as they are printing presses and I dont have all the info at hand right now for those. If you have anything that you think might be useful to me please feel free to send it over. The spreadsheets sound particularly useful if you didnt mind sharing but obviously I respect the fact its your work and intellectual property etc and fully understand if you wanted to hang on to them.
bleve  
#14 Posted : 27 July 2010 09:43:19(UTC)
Rank: Super forum user
bleve

Head space of tanks Zone 1 3 metres in all directions from vent Zone 2 Entire area of bund Zone 2 Any pump sump within the bund Zone 1. Tanker loading area will be zone 2 extent depending on size of discharge line, couplings and pressure or as a rule of thumb take the unloading area bund as pool size and calculate extent of zone above and beyond it.
bleve  
#15 Posted : 27 July 2010 09:44:08(UTC)
Rank: Super forum user
bleve

Sorry head space of tank should state Zone 0 Vent Zone 1.
bob youel  
#16 Posted : 27 July 2010 09:47:02(UTC)
Rank: Super forum user
bob youel

what has happened to HAZAN HAZOPS and similar tools as this ouunds like a situation where a safety case 'bod' is required
ITER  
#17 Posted : 27 July 2010 11:31:28(UTC)
Rank: Forum user
ITER

Jason I assume you/your company is the client? If the tanks are yet to be installed on your behalf and hence designed by someone else - then the designers should undertake the various hazardous area calculations, so the vents can be sized properly, equipment specified etc. They should pass the information on to you and/or you should get the information from the layout engineering drawings of the tank and system etc. The figures quoted by others/Zone classifications will be ok. From the information you now appear to have given, I'm not so sure you need to get involved with the calcs. Just take the design calculations and make site personnel aware etc for future reference e.g. when undertaking maintenance, allowing heat sources into the area, electrical equipment etc. bob - HAZOPS/HAZANs studies will simply tell you to that you need to calculate/estimate the extent of the hazardous areas to comply with DSEAR. And yes I am a safety case engineer 'bod'
JasonMcQueen  
#18 Posted : 27 July 2010 13:35:05(UTC)
Rank: Forum user
JasonMcQueen

Your correct, the company is the client. I'll speak to our Engineering manager about getting the contractor to provide the correct info. What do I do regarding the printing presses etc which use solvent based inks in their process? I still need to calculate the extent of the zones from the source.
bleve  
#19 Posted : 27 July 2010 14:04:10(UTC)
Rank: Super forum user
bleve

Tank fabricator will only size vents and pressure relief PSV based on breathing losses for atmsopheric storage tanks and fire case for pressure vessels. This will not have an input into the HAC. The only calculation necessary will be that of jet/spray release from tanker unloading hose, comparison of extent of unloading area bund. In addition, consider any flanges in transfer lines from bulk storage tanks into process building and of course emission points at the printing equipment. Also consider that your explosive limits will be far in excess of your IH limits.
JasonMcQueen  
#20 Posted : 27 July 2010 15:05:35(UTC)
Rank: Forum user
JasonMcQueen

Ok, the more I read on this, the more I think Im going to out source. Having read more guidance documents than I care to remember (Im now on IP part 15) and having set up a spreadsheet to calculate the formulas in the BS, I still dont see any correlation between any figures and the appropriate extent of the zoning. The BS formulas allow you to calculate the leakage rate, the volume of the substance in the area, the rate of air changes etc but I dont understand how you move from this to saying for example, 3m horizontal and 2m vertical for a given situation. Am I missing something?
bleve  
#21 Posted : 27 July 2010 15:20:51(UTC)
Rank: Super forum user
bleve

60079 does not take into account liquid jet release, formation of pools, pool evaporation rate, mixtures of liquids or gases, effect on extent of zone due to obstructions etc. The BS also clearly states that this exercise should be carried out by an expert. As previously stated the extent of zoning associated with the storage tanks can be determined by exemplar (the extent I have already described). The extent of other zones particularly in relation to the machinery you describe will need to be determined through study and calculation.
bleve  
#22 Posted : 27 July 2010 15:40:07(UTC)
Rank: Super forum user
bleve

Jason, If you have got to the point where you have calculated a value for Vz, then you can calculated a radius of a sphere based on the volume calculated: REMEMBER that this is the radius of a perfect sphere and depending on conditions and properties of the GAS or VAPOUR released THE IDENTIFIED AREA may or may not be spherical. This will not allow you to calculate the extent of zone over and beyond a liquid pool and will not be of use for jet release. you need to use other formulae for these cases :) Radius = Volume of Vz / 4/3 x PI ^1/3 plug this into excel = (your value of Vz/((4/3)*(3.142)))^0.33 regards
JasonMcQueen  
#23 Posted : 27 July 2010 15:43:39(UTC)
Rank: Forum user
JasonMcQueen

Point taken. I guess I just wanted to be able to work it out for myself. I dont like not being able to do something and was hoping that with enough reading and research I'd be able to figure it out.
JasonMcQueen  
#24 Posted : 27 July 2010 16:17:25(UTC)
Rank: Forum user
JasonMcQueen

That was strange. Your last reply didnt show until after I had posted my reply to your previous one.. Anyway, yes I've reached the point of calculating the corrected Vz but looking at the worked exapline in 60079 I think my calculation for calcuating air changes (c) is off. They list it as dV0/dt over V0. But in their worked example on page 33 they have a room with 900m2 and a minimum volumetric flow rate of 2.3x10^-8 m3/s but they show the number of air changes as 2.8x10^-4s. I would have it that 2.3x10^-8 divided by 900 is 2.5x10^-11? Obviously Im missing something somewhere. Is dv0/dt different to (dV/dt)min and if so, how as it doesnt explain how to calculate the total flow rate of fresh air through the volume under consideration only minimum volumetric flow rate m3/s Sorry for all the questions and thanks for sticking with me on this. I probably will go with a third party but I'd still like to understand the workings so I can ensure we appoint a decent consultant.
ITER  
#25 Posted : 27 July 2010 16:20:03(UTC)
Rank: Forum user
ITER

The IP 15 tables and standard examples contained in the guide should suffice for what you need. Hazardous area calcs are not an exact science - IP 15 is a pragmatic guide based on conservative engineering judgement. You could also read a book by Frank Lees -'Loss Prevention in the Process Industeries'.... but it is about 900pages long! ok maybe not. He has also written another book specifically about hazardous area classification - the exact title slips my mind right now - but if you Google Frank Lees, I'm sure you should be able to track it down quite easily. As for the other printing machines etc you mention - if the pipes containing flammable are small, then its probably unlikely that the haz zones will be greater than 1-2m. As regards spherical zones - correct, thats the advantage of using PHAST you can factor in weather conditions, wind direction and strength etc to get a pretty picture showing the calculated extent of the cloud. Given the basis for the ventilation in 60079-10 is a best guess fudge factor, if you use a factor that is more conservative i.e. worse ventilation, then in practice, for external tanks/pipes the haz zone will in practice be smaller. Remember 60079-10 assumes ventialtion wind speeds outside are rarely less than 0.5m/s. Disagree that the tank fabricator will only size atmospheric vents - I have worked for 2-3 design consultant companies in the oil/gas sector - we always did the full haz zone calcs using IP15 and/or 60079-10 and passed on the results to the client. Just insist that you get them supplied by the designers!
bleve  
#26 Posted : 27 July 2010 16:30:43(UTC)
Rank: Super forum user
bleve

Cox, Lees & Ang
bleve  
#27 Posted : 27 July 2010 22:24:34(UTC)
Rank: Super forum user
bleve

ITER wrote:
if the pipes containing flammable are small, then its probably unlikely that the haz zones will be greater than 1-2m. if you use a factor that is more conservative i.e. worse ventilation, then in practice, for external tanks/pipes the haz zone will in practice be smaller.
But the zone willbe dependant on the distance and size of any pool formed. If ventilation decreases in actual fact the hazardous area (extent of zone) increases.
bleve  
#28 Posted : 27 July 2010 22:28:49(UTC)
Rank: Super forum user
bleve

Jason, if I figure out which version you are using I will try and explain by example
bleve  
#29 Posted : 27 July 2010 22:35:29(UTC)
Rank: Super forum user
bleve

JasonMcQueen wrote:
One source I spoke to said that provided I justify the decision on what zoning to assign to the souce, the actual extent isnt necessary.
Jason, go back to your source and aske him/her,if you do not know the extent of a zone how can you ensure that the electrical and or mechanical equipment is suitable for use within the extent of the zone?what about zone transition?
ITER  
#30 Posted : 27 July 2010 22:55:08(UTC)
Rank: Forum user
ITER

Quite right, if the ventialation is assumed to be worse than actual, you will get a bigger haz area, which is more conservative - if it fact this is not the case. Hence unsuitable electrical equipment etc will be kept at a safe distance from the actual hazarous area.
bleve  
#31 Posted : 27 July 2010 23:07:03(UTC)
Rank: Super forum user
bleve

I actually understand what you are saying, from one safety case bod to another I hope you are not as cryptic in any safety case document though.
bleve  
#32 Posted : 28 July 2010 10:44:54(UTC)
Rank: Super forum user
bleve

Jason
Quote:
Molecular Weight of substance 92.14
Quote:
LEL 1.2% (Convert LEL to mass per volume Kg/m3) = 0.416*10^-3*92.14*1.2 = 0.046 Kg/m3
Quote:
Ventilation safety factor k = 0.25
Quote:
Release rate (dG/dt)max = 2.8*10^-10 Kg/s
Quote:
Ventilation
Quote:
No. of air changes ( C ) = 1/hour. Calculated air change per second: 1/3600 = 2.8*10^-4/second
Quote:
Quality factor = 5
Quote:
Temperature = 293 Kelvin
Quote:
Building volume Vo = 900 m^3
Quote:
Minimum volumetric flow rate of fresh air: (dV/dt) min
Quote:
= (dG/dt)max /k*LEL * T/293 = 2.8*10^-10 Kg/s / (0.25 * 0.046) 8 293 / 293 = 2.4 * 10^-8 m^3/second
Quote:
Hypothetical volume Vz
Quote:
= f * (dV/dt)min / C = 5 * 2.4 * 10^-8 /2.8 * 10^-4 = 4.3 *10^-4
Quote:
Radius of hazardous area = (Vz/((4/3)*(3.142)))^0.33 = 0.048 metres
Quote:
Throwing some light on the relationship between the calculated value of (dV/dt)min and the actual ventilation rate within the volume under consideration (Vo) in the vicinity of a release, which is expressed as Vk.
Quote:
Vk = (dV/dt)min / C
Quote:
Where C is the number of fresh air changes per unit time (S-1), derived from C = dVo/delta t / Vo
Quote:
dVo/dt is the total flow rate of fresh air through the volume of consideration
Quote:
Vo is the entire volume served by the actual ventilation in the vicinity of the release being considered.
Quote:
Now we know that C = 1 air change per hour and (0.00028 air change per second) We also know the Volume under consideration Vo = 900 m^3
Quote:
So dVo/dt = 900 m^3/3600 = 0.25 m^3/second
Quote:
Therefore C = dVo/dt / Vo = (0.25m^3/s) / 900 = 0.00028 AC/second
Quote:
Remember that Vz = f * Vk = (f * (dV/dt)min) / C meaning that you do not have to bother with calculating Vk.
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