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MrBrightside  
#1 Posted: : 01 November 2024 11:58:26(UTC)
Rank: Forum user
MrBrightside

Hi All,

Just doing some looking around the web for similar companies that publish their own rates (been asked to look at comparisons). Now maths is by no means my strong point and I am looking at data published by the Hs2 project, can someone who is a lot smarter than me, explain how they get a rate lower than zero? 

Thank you

thanks 3 users thanked MrBrightside for this useful post.
Kate on 01/11/2024(UTC), MikeKelly on 01/11/2024(UTC), peter gotch on 04/11/2024(UTC)
Kate  
#2 Posted : 01 November 2024 13:08:51(UTC)
Rank: Super forum user
Kate

It's Friday afternoon and I want to see this.  Can you give a link?

MrBrightside  
#3 Posted : 01 November 2024 13:14:51(UTC)
Rank: Forum user
MrBrightside

I did a bit more digging, its something to do with rating accident type in terms of seriousness when you do the calculation. Apprently its a better way

https://safety.hs2.org.uk/how-were-performing/

Kate  
#4 Posted : 01 November 2024 13:18:11(UTC)
Rank: Super forum user
Kate

Well obviously it's a totally brilliant way if it gets your rate below zero.  Zero harm is evidently old hat, less than zero is the new aim!

Kate  
#5 Posted : 01 November 2024 13:23:52(UTC)
Rank: Super forum user
Kate

None of the several frequency rates I see on that page are below zero though.  The lowest of them is 0.06.  An accident rate below zero would have a minus sign in front of it and would be calculated in a truly innovative way.

Mirin  
#6 Posted : 01 November 2024 13:24:43(UTC)
Rank: New forum user
Mirin

chris42  
#7 Posted : 01 November 2024 13:42:18(UTC)
Rank: Super forum user
chris42

Did someone think about doing some work, then decided against it resulting in a negative number of hours worked.

So accident numbers multiplied by whichever number you use ( 100,000 or 200,000) gives a positive number. A positive number divided by a negative one gives you a negative rate. Obviously, the number of accidents can not be zero for this to work.

thanks 1 user thanked chris42 for this useful post.
peter gotch on 04/11/2024(UTC)
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